CONCRETE MIX DESIGN OF M25 GRADE – AS PER IS 10262:2019

1.STIPULATIONS FOR PROPORTIONING

a) Grade designation : M 25 RCC

b) Type of cement : 43 grade Ordinary Portland Cement conforming IS 8112

c) Maximum nominal size of coarse aggregate : 20 mm

d) Minimum amount of cement  : 300 kg/m³ as per IS 456

e) Maximum water-cement ratio : 50 as per Table 5 of IS 456:2000

f) Workability : 75-125 mm slump

g) Exposure condition : Moderate (For Reinforced Concrete)

h) Method of concrete placing : Pumping

j) Degree of supervision : Good

k) Type of aggregate : Crushed Angular Aggregates

l) Chemical admixture type : Super Plasticizer Normet

2.TEST DATA FOR MATERIALS

a) Cement used : Sagar 43 grade Ordinary Portland cement conforming IS 8112

b) Specific gravity of cement : 3.14

c) Chemical admixture : Super Plasticizer conforming to IS 9103 

d) Specific gravity of

1) Coarse aggregate 20 mm : 2.799

2) Coarse aggregate 10 mm: 2.789

3)Combined Specific Gravity of aggregate ( 20 mm- 60% & 10 mm 40 % )=2.795

4) Fine aggregate : 2.517

e) Water absorption:

1) Coarse aggregate 20 mm : 0.41 %

2) Coarse aggregate 10 mm  : 0.59 %

3) Fine aggregate           : 1.87 %

f) Aggregate Impact Value : 20.52%

g) Combined Flakiness & Elongation Index : 27.57 %

h) Sieve analysis:

1) Coarse aggregate: Conforming to all in aggregates of Table 2 of IS 383

2) Fine aggregate : Conforming to Grading Zone III of Table 4 of IS 383

3 TARGET STRENGTH FOR MIX PROPORTIONING

f’ck =fck + 1.65 s   Or  f’ck = fck + X  where

f’ck = average target compressive strength of concrete at 28 days,

fck = characteristics compressive strength of concrete at 28 days,

X   = Factor based on grade of concrete

S = standard deviation. From table 2 of IS 10262-2019  S = 4 N/mm² & from table 1 , X=5.5

Therefore target strength of concrete using both equation

.

a) f’ck= fck+ 1.65 S  = 25 + 1.65 x 4 = 31.60 N/mm²

b) f’ck = fck+ X        = 25 +  5.5 =  30.5 N/mm².

The higher value to be adopted , therefore target strength will be 31.60 N/mm². Can adopt  this value while doing the concrete mix design those who are working other than highway project.

But as per MORT&H Table 1700.5 required target mean compressive strength = 25 + 11 = 36.00 N/mm²  where 11 is the current margin. Adopt this value those who are working in highway project.

4. APPROXIMATE AIR CONTENT

From Table 3, the approximate amount of entrapped air to be expected in normal (non-air-entrained) concrete is 1.0 percent for 20 mm nominal maximum size of aggregate.

5 SELECTION OF WATER-CEMENT RATIO

From Fig. 1 of IS 10262 -2019, the free water-cement ratio required for  the target strength  of  31.60 N /mm²  is 0.48 may be used for OPC 43 grade curve. (For other than MORT&H)

Maximum water cement ratio required for the target strength of 36.00 N /mm²(As per MORT&H requirement)  is 0.44  from figure 1 of IS 10262-2019.

My suggestion & experience , never adopt higher water cement ratio  because it is the main reason for cube failure at site. In IS code , suggestion has been given for adopting the water cement ratio but concrete designer has to take the decision what to keep water cement ratio.

Based on trial & experience adopted 0.44 water cement ratio.

 This is lower than the maximum value of 0.50 prescribed for from the Table 3 of IS 456 maximum Water Cement Ratio for moderate condition

As per MORT&H, maximum water cement ratio is 0.45 for moderate condition  so 0.44 is satisfying  all codal provision  whether it is  IS 456 or MORT&H

0.44 < 0.50 < 0.45 hence ok.

6. SELECTION OF WATER CONTENT

From Table 4 of IS 10262:2019, maximum water content for 20 mm aggregate = 186 liter (for 25 to 50 mm slump range)

but for an increase by about 3 percent for every additional 25 mm slump so here estimated water content for 125 mm slump

= 186+(9/100) x 186

= 202 liter.       

Based on trials with Super plasticizer water content reduction of 23.76 % has been achieved . How it comes ,

We will see the back calculation

(Water requirement , if  we intended to keep cement 350 kg  &  w/c ratio 0.44 for our concrete mix design  calculated water will be 154 liter ,  so required reduction in water when using superplaticizer  = 100 – (154/202 x 100) = 23.76 %.)

Net required water = 202 (202 x 23.76) % = 202 – 48 = 154.0 litre

Note :For 75 mm slump increase 3% , for 100 mm increase 6% , increase 9 % for 125 mm slump, increase 12 % for 150 mm slump & increase 15 % for 175 mm slump

7 CALCULATION OF CEMENT CONTENT

As discuss earlier adopted  based on trial w/c Ratio = 0.44

Cement Content = 154/0.44 = 350 kg/m³

,from Table 5 of IS 456, minimum cement content for ‘moderate’ exposure conditions is 300 kg/m³  but taken  350 kg/m³ > 300 kg/m³ hence ok.

As per MORT&H 5th revision for moderate exposure  with reference to Table number 1700-2  maximum water cement ratio 0.45 & minimum cement 340 kg/m³ is specified but we had taken 350 kg/m³ , hence ok

but we had taken 350 kg/m³ > 340 kg/m³ hence ok. 

8 PROPORTION OF VOLUME OF COARSE AGGREGATE AND FINE AGGREGATE CONTENT

As per table number 5 of IS 10262:2019 volume of coarse aggregate for 20 mm nominal size aggregate and fine aggregate (Zone III) for having water-cement ratio of 0.50 =0.64 (a)

20 mm aggregate and fine aggregate (Zone III) for having water-cement ratio of 0.50 =0.64 (a)

In the present case water-cement ratio is 0.44. Therefore. volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.06. the proportion of volume of coarse aggregate is increased by 0.012 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio).

= (0.06/0.05) = 1.2 times of 0.01 so  0.01 x 1.2 = 0.012 (b)

a+b = 0.64 + 0.012 =0.65  (at the rate of -/+ 0.01 for every ± 0.05 change in w/c ratio).

Therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.44 = 0.65

For pumpable concrete these values should be reduced up to 10%. Therefore, volume of coarse aggregate =0.65 x 0.9 =0.585 or say 0.59

Volume of fine aggregate content = 1 – 0.59 = 0.41

9 MIX CALCULATIONS

The mix calculations per unit volume of concrete shall be as follows:

a)Volume of concrete = 1

b)Volume of the entrapped air in wet concrete =0.01m³ 

c) Volume of cement = [Mass of cement] / {[Specific Gravity of Cement] x 1000}

= 350/{3.15 x 1000} = 0.111

d) Volume of water = [Mass of water] / {[Specific Gravity of water] x 1000}

= 154/{1 x 1000} = 0.154

e) Base on trial we had kept admixture 50 percentage by weight of cement(You can increase % admixture dosage as per requirement)

 Volume of admixture  = [Mass of admixture ] / {[Specific Gravity of admixture ] x 1000}

= 1.75 /{1.090 x 1000}

= 0.0016

f) Volume of all in aggregate = [(a-b)-(c+d+e)]

= [(1-0.01)-(0.111+0.154+0.0016)]= 0.99-0.250

= 0.723

g) Mass of coarse aggregate= e x Volume of Coarse Aggregate x Specific Gravity of coarse Aggregate x 1000

= 0.723 x 0.59 x 2.795 x 1000

= 1192.26 kg/m³

h) Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

= 0.723 x 0.41 x 2.517 x 1000

= 746.11 kg/m³

10  MIX proportion

Cement = 350 kg/m³

Water = 154 l/m³

Fine aggregate = 746.11 kg/m³

Coarse aggregate 20 mm = 1192.26 x 60 %= 715.36 kg/m³

Coarse aggregate 10 mm  = 1192.26 x 40 %= 476.90 kg/m³

Chemical admixture = 1.75 kg/m³ 

Water-cement ratio = 0.44

11 CALCULATION

1.Aggregate 20 mm  = 715.26/ (1+(0.41/100)}           = 712.0 kg

2. Aggregate 10 mm = 476.90/ (1+(0.59/100)}         = 474.0 kg       

3.Sand                            = 746.11/ (1+(1.87/100)}           = 732.0 kg

4.Water                        = 2444 – 350 – 1.75 -732 -712 – 474  = 174.25 kg 

Can  say 174 kg  alternatively can calculate in the following manner.

 154+(746.11-732.0) +(715.26-712) +(476.90-474) = 154 + 14.11 + 3.26 + 2.90 = 174.27  or say 174 kg

Note 1.Do the trial in dry position as in practical in batching plant you can cot use aggregate in SSD condition.

2.Do the number of trials with variation of ± 10 percent of water-cement ratio & different cement content,

3.Do the surface moisture correction whenever required.

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Concrete Mix Design Of M35 Grade(Pile) as per IS 10262:2009

1.STIPULATIONS FOR PROPORTIONING

a) Grade designation : M35 RCC (Pile)

b) Type of cement :53 grade Ordinary Portland Cement conforming IS 12269

c) Maximum nominal size of coarse aggregate : 20 mm

d) Minimum amount of cement  : 400 kg/m³ as IS 2911-Part 1/Sec 2 & IRC 78-2014.

e) Maximum water-cement ratio : 0.40 as per IRC 78 -2014 ,Cl  709.1.9

f) Workability : 150-200 mm slump as per IRC 78-2014 , Cl  709.1.9

g) Exposure condition : Moderate (For Reinforced Concrete)

h) Method of concrete placing : Trieme

j) Degree of supervision : Good

k) Type of aggregate : Crushed Angular Aggregates

l) Chemical admixture type : Super Plasticizer Normet

2.TEST DATA FOR MATERIALS

a) Cement used : Sagar 53 grade Ordinary Portland cement conforming IS 12269

b) Specific gravity of cement : 3.14

c) Chemical admixture : Super Plasticizer conforming to IS 9103 

d) Specific gravity of

1) Coarse aggregate 20 mm : 2.799

2) Coarse aggregate 10 mm: 2.789

Combined Specific Gravity of aggregate ( 20 mm-45% & 10 mm 55% )=2.792

2) Fine aggregate : 2.517

e) Water absorption:

1) Coarse aggregate 20 mm : 0.41 %

2) Coarse aggregate 10 mm  : 0.59

3) Fine aggregate           : 1.87 %

f) Aggregate Impact Value : 20.52

g) Combined Flakiness & Elongation Index : 27.57 %

h) Sieve analysis:

1) Coarse aggregate: Conforming to all in aggregates of Table 2 of IS 383

2) Fine aggregate : Conforming to Grading Zone III of Table 4 of IS 383

3 TARGET STRENGTH FOR MIX PROPORTIONING

f’ck =fck + 1.65 s    where

f’ck = average target compressive strength of concrete at 28 days,

fck = characteristics compressive strength of concrete at 28 days,

S = standard deviation.From table 1 of  IS 456 & IS 10262  assumed Standard Deviation, s = 5 N/mm² ; therefore target strength of concrete = 35 + 1.65 x 5 = 43.25 N/mm². Can adopt  this value while doing the concrete mix design those who are working other than highway project.

But as per MORT&H Table 1700.5 required target mean compressive strength = 35 + 12 = 47.00 N/mm²  where 12 is the current margin. Adopt this value those who are working in highway project.

4 SELECTION OF WATER•CEMENT RATIO

Based on the trial , adopted water cement ration 0.40

From the Table 5 of IS 456 maximum Water Cement Ratio for moderate condition is 0.50

As per Section 709.1.9 of IRC 78, maximum water cement ratio is 0.40 

so 0.40 is satisfying  all codal provision  whether it is  IS 456 or MORT&H

0.40 < 0.50 = 0.40 hence ok.

 5 SELECTION OF WATER CONTENT

From Table 2 of IS 10262:2009, maximum water content for 20 mm aggregate = 186 litre (for 25 to 50 mm slump range)

but for an increase by about 3 percent for every additional 25 mm slump so here estimated water content for 175 mm slump

= 186+(15/100) x 186

= 213.9 or 214 liter.

Based on trials with Super plasticizer water content reduction of 21.50% has been achieved.How it comes , see below calculation:

Water requirement , if  we intended to keep cement 420 kg for &  w/c ratio 0.40 for our concrete mix design  calculated water will be 168.0 liter ,  so required reduction in water when using superplaticizer  = 100 – (168/214 x 100) = 21.50 %.

Net required water = 214 – (214 x 21.50) % = 214 –46.1 = 167.99 liter say 168 liter.

Note :For 75 mm slump increase 3% , for 100 mm increase 6% , increase 9 % for 125 mm slump, increase 12 % for 150 mm slump & increase 15 % for 175 mm slump

6 CALCULATION OF CEMENT CONTENT

As discuss earlier adopted  based on trial w/c Ratio = 0.40

Cement Content = 168.0/0.40 = 420 kg/m³

As per IS 2911-Part 1/Sec 2 minimum cement content for tremie concrete is 400 kg/m³.

(As per Section 709.1.9 of IRC 78 – 2014 minimum cement content  400 kg & maximum water cement ratio is 0.40 specified)

but we had taken 420 kg/m³ > 400 kg/m³ hence ok.

7 PROPORTION OF VOLUME OF COARSE AGGREGATE AND FINE AGGREGATE CONTENT

As per table number 3 of IS 10262:2009 volume of coarse aggregate for 20 mm nominal size aggregate and fine aggregate (Zone III) for having water-cement ratio of 0.50 =0.64 (a)

In the present case water-cement ratio is 0.40. Therefore. volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.10. the proportion of volume of coarse aggregate is increased by 0.02 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio). As the water-cement ratio is lower by 0.10. The proportion of volume of coarse aggregate is increased by

= (0.10/0.05) = 2.0 times of 0.01 so  0.01 x 2.0= 0.020 (b)

=  a+b = 0.64 + 0.020 =0.66

(at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio).

Therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.40 = 0.66

NOTE – In case the coarse aggregate is not angular one, then also volume of coarse

aggregate may be required to be increased suitably based on experience & Site conditions.

For pumpable concrete these values should be reduced up to 10%. Therefore, volume of coarse aggregate =0.66 x 0.9 =0.59.

Volume of fine aggregate content = 1 – 0.59 = 0.41.

8 MIX CALCULATIONS

The mix calculations per unit volume of concrete shall be as follows:

a) Volume of concrete = 1 m³

b) Volume of cement = [Mass of cement] / {[Specific Gravity of Cement] x 1000}

= 420/{3.15 x 1000} = 0.133 m³

c) Volume of water = [Mass of water] / {[Specific Gravity of water] x 1000}

= 168.0/{1 x 1000} = 0.168 m³

d) Base on trial we had kept admixture 1.0 percentage by weight of cement

 Volume of admixture  = [Mass of admixture ] / {[Specific Gravity of admixture ] x 1000}

= 4.2 /{1.090 x 1000}

= 0.0039 m³

e) Volume of all in aggregate = [a-(b+c+d)]

= [1-(0.133+0.168+0.0039)]

= 0.695 m³

f) Mass of coarse aggregate= e x Volume of Coarse Aggregate x Specific Gravity of  coarse Aggregate x 1000

= 0.695 x 0.59 x 2.792 x 1000

= 1144.86 kg/m³

g) Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

= 0.695 x 0.41 x 2.517 x 1000

= 724.22 kg/m³

9 MIX PROPORTIONS

Cement = 420 kg/m³

Water = 168.0 l/m³

Fine aggregate = 724.22 kg/m³

Coarse aggregate 20 mm = 1144.86 x 45 %= 515.19 kg/m³

Coarse aggregate 10 mm  = 1144.86 x 55%= 629.67 kg/m³

Chemical admixture = 4.2 kg/m³ 

Water-cement ratio = 0.40

Calculation :

1. Aggregate 20 mm= 515.99/ (1+(0.41/100)}      = 514.0 kg

2. Aggregate 10 mm = 629.67/ (1+(0.59/100)}    = 725 kg  

3. Sand                           = 724.44/ (1+(1.87/100)}    = 626.0 kg

3. Water                         =  2460-420-711-514-626  = 189          

NOTE 

1.Do the trial in dry position as in practical in batching plant you can cot use aggregate in SSD condition.

2.Batch for trial is given in dry position.

3.Do the number of rials with variation of ± 10 percent of water-cement ratio & different cement content

4.Do the surface moisture correction whenever required.

 

 

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Concrete Mix Design for M25 grade as per IS 10262:2009

1.STIPULATIONS FOR PROPORTIONING

a) Grade designation : M25 RCC

b) Type of cement :53 grade Ordinary Portland Cement conforming IS 12269

c) Maximum nominal size of coarse aggregate : 20 mm

d) Minimum amount of cement  : 300 kg/m³ as per IS 456:2000

e) Maximum water-cement ratio : 0.50 as per Table 5 of IS 456:2000

f) Workability : 100 – 125 mm slump

g) Exposure condition : Moderate (For Reinforced Concrete)

h) Method of concrete placing : Pumping

j) Degree of supervision : Good

k) Type of aggregate : Crushed Angular Aggregates

l) Chemical admixture type : Super Plasticizer Normet

2.TEST DATA FOR MATERIALS

a) Cement used : Sagar 53 grade Ordinary Portland cement conforming IS 12269.

b) Specific gravity of cement :3. 15

c) Chemical admixture : Super Plasticizer conforming to IS 9103.

d) Specific gravity of

1) Coarse aggregate 20 mm : 2.799

2) Coarse aggregate 10 mm: 2.789

3) Combined Specific Gravity of aggregate

( 20 mm-45% & 10 mm -55% )=2.792.

4) Fine aggregate : 2.517

e) Water absorption:

1) Coarse aggregate 20 mm : 0.41 %

2) Coarse aggregate 10 mm  : 0.59 %

3) Fine aggregate                      : 1.87 %

f) Aggregate Impact Value : 20.52 %

g) Combined Flakiness & Elongation Index : 27.57 %

h) Sieve analysis:

1) Coarse aggregate: Conforming to all in aggregates of Table 2 of IS 383

2) Fine aggregate : Conforming to Grading Zone III of Table 4 of IS 383

3 TARGET STRENGTH FOR MIX PROPORTIONING

f’ck =fck + 1.65 s

where

f’ck = average target compressive strength of concrete at 28 days,

fck = characteristics compressive strength of concrete at 28 days, and

s = standard deviation.

From table 1 of  IS 10262 assumed Standard Deviation, s = 4 N/N/mm². Therefore, target strength of concrete = 25 + 1.65 x 4 = 31.6 N/mm².

But as per MORT&H 5th revision Table 1700.5 required target mean compressive strength = 25 + 11 = 36.00 N/mm²  where 11 is the current margin.

4 SELECTION OF WATER•CEMENT RATIO

Based on the trial , adopted water cement ratio 0.38

From the Table 5 of IS 456 maximum Water Cement Ratio is 0.50

0.38 < 0.50 Hence ok.

As per MORT&H 5th revision Maximum Water Cement Ratio water cement ratio for moderate exposure is 0.45 , hence it is ok

 5. SELECTION OF WATER CONTENT

From Table 2 of IS 10262:2009, maximum water content for 20 mm aggregate = 186 liter for 25 to 50 mm slump range but for an increase by about 3 percent for every additional 25 mm slump so here estimated water content for 125 mm slump = 186+(9/100) x 186 = 202 liter.

Water requirement if we are considering cement 360 kg & w/c ratio o.38 for concrete mix design ; calculated water will be  136.8 so net  reduction in water while using super plasticizer = 100 – (136.8/202 x 100) = 32.28 %.

Now we had got  reduction percentage of water , calculate of the required water = 202 – (202 x 32.28) % = 202 – 65.20 = 136.80 (For 75 mm slump increase 3% , for 100 mm increase 6% & increase 9 % for 125 mm slump) 

6. CALCULATION OF CEMENT CONTENT

Adopted w/c Ratio = 0.38   then Cement Content = 136.80/0.38 = 360 kg/m³ ,from Table 5 of IS 456, minimum cement content for ‘moderate’ exposure conditions is 300 kg/m³  but taken  360 kg/m³ > 300 kg/m³ hence ok.

As per MORT&H 5th revision for moderate exposure  with reference to Table number 1700-2  maximum water cement ratio 0.45 & minimum cement 340 kg/m³ is specified but we had taken 360 kg/m³ , hence ok

7. CALCULATION OF COARSE AGGREGATE AND FINE AGGREGATE PROPORTION

From Table 3 of (IS 10262:2009) Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone III) for water-cement ratio of 0.50 =0.64 (a)

In the present case water-cement ratio is 0.38 therefore, volume of coarse aggregate is required to be increased to decrease the fine  aggregate content.

As the water cement ratio is lower by 0.12 , the proportion of volume of  coarse aggregate  is increased by= (0.12/0.05) = 2.4 times of 0.01 ,so  0.01 x 2.4= 0.024 (b)

Net required water cement ratio= a+b = 0.64 + 0.024 =0.66(at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio) therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.38 = 0.66

NOTE – In case the coarse aggregate is not angular one, then also volume of coarse aggregate may be required to be increased suitably based on experience & Site conditions.

If we are doing concrete with pump , reduce upto 10% these value ,therefore volume of coarse aggregate =0.66 x 0.9 =0.59.

Actual reduced volume of fine aggregate content = 1 – 0.59 = 0.41.

8. MIX CALCULATIONS

Determination of mix calculation will be as under:

a)Volume of concrete = 1 m³

b)Volume of cement = [Mass of cement] / {[Specific Gravity of Cement] x 1000}  = 360/{3.15 x 1000} = 0.115 m³

c)Volume of water = [Mass of water] / {[Specific Gravity of water] x 1000}

= 136.80/{1 x 1000} = 0.136 m³

d) Base on trial we had kept admixture 0.45 percentage by weight of cement

 Volume of admixture  =  [Mass of admixture ] / {[Specific Gravity of admixture ] x 1000}

= 1.62 /{1.090 x 1000} = 0.00149 m³

e)Volume of all in aggregate = [a-(b+c+d)]

= [1-(0.115+0.134+0.00149)] = 0.750 m³

f)Mass of coarse aggregate= e x Volume of Coarse Aggregate x Specific Gravity of coarse Aggregate x 1000

= 0.750 x 0.59 x 2.792 x 1000 = 1235.46 kg/m³

g)Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

= 0.750 x 0.41 x 2.517 x 1000 = 773.98 kg/m³

9. MIX PROPORTIONS

Cement = 360 kg/m³

Water = 136.80 l/m³

Fine aggregate = 834 kg/m³

Coarse aggregate 20 mm = 1235.46 x 45 %= 555.96 kg/m³

Coarse aggregate 12 mm  = 1235.46 x 55%= 679.50 kg/m³

Chemical admixture = 1.62 kg/m³ 

Water-cement ratio = 0.38

   

1.Aggregate 20 mm  = 555.96/ (1+(0.41/100)}                     = 554.0 kg

2. Aggregate 10 mm = 679.50/ (1+(0.59/100)}                   = 676.0 kg

3.Sand                            = 834.0/ (1+(1.87/100)}                      = 819.0 kg

4.Water                         = 2568 -360 – 819 -554 – 676      = 160.0 kg       

NOTE

1.Do the trial in dry position as in practical in batching plant you can cot use aggregate in SSD condition.

2.Batch for trial is given in dry position.

3.Do the number of rials with variation of ± 10 percent of water-cement ratio & different cement content

4.Do the surface moisture correction whenever required.

 

 

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